From 88ce15fb62cf615cdae0703c6361373644906f13 Mon Sep 17 00:00:00 2001
From: Oskari Timperi <oskari.timperi@iki.fi>
Date: Wed, 13 Feb 2013 22:57:50 +0200
Subject: problem1

---
 CMakeLists.txt    |  2 ++
 p1/CMakeLists.txt |  2 ++
 p1/main.c         | 27 +++++++++++++++++++++++++++
 3 files changed, 31 insertions(+)
 create mode 100644 CMakeLists.txt
 create mode 100644 p1/CMakeLists.txt
 create mode 100644 p1/main.c

diff --git a/CMakeLists.txt b/CMakeLists.txt
new file mode 100644
index 0000000..72c67ef
--- /dev/null
+++ b/CMakeLists.txt
@@ -0,0 +1,2 @@
+cmake_minimum_required(VERSION 2.8)
+add_subdirectory(p1)
diff --git a/p1/CMakeLists.txt b/p1/CMakeLists.txt
new file mode 100644
index 0000000..5bd9bd6
--- /dev/null
+++ b/p1/CMakeLists.txt
@@ -0,0 +1,2 @@
+PROJECT(euler_problem1 C)
+ADD_EXECUTABLE(p1 main.c)
diff --git a/p1/main.c b/p1/main.c
new file mode 100644
index 0000000..e227e80
--- /dev/null
+++ b/p1/main.c
@@ -0,0 +1,27 @@
+/*
+ * If we list all the natural numbers below 10 that are multiples of 3 or 5,
+ * we get 3, 5, 6 and 9. The sum of these multiples is 23.
+ *
+ * Find the sum of all the multiples of 3 or 5 below 1000.
+ */
+
+#include <stdio.h>
+
+int main(int argc, char **argv)
+{
+
+	int sum = 0;
+	int i;
+
+	for (i = 1; i < 1000; ++i)
+	{
+		if (i % 3 == 0 || i % 5 == 0)
+		{
+			sum += i;
+		}
+	}
+
+	printf("sum: %d\n", sum);
+
+	return 0;
+}
-- 
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